Jak znaleźć czas trwania różnicy między dwiema datami w Javie?

Mam dwa obiekty DateTime , które muszą znaleźć czas trwania ich różnicy ,

Mam następujący kod, ale nie wiem, jak go kontynuować, aby uzyskać oczekiwane wyniki w następujący sposób:

Przykład

      11/03/14 09:30:58
      11/03/14 09:33:43
      elapsed time is 02 minutes and 45 seconds
      -----------------------------------------------------
      11/03/14 09:30:58 
      11/03/15 09:30:58
      elapsed time is a day
      -----------------------------------------------------
      11/03/14 09:30:58 
      11/03/16 09:30:58
      elapsed time is two days
      -----------------------------------------------------
      11/03/14 09:30:58 
      11/03/16 09:35:58
      elapsed time is two days and 05 mintues

Kod

    String dateStart = "11/03/14 09:29:58";
    String dateStop = "11/03/14 09:33:43";

    Custom date format
    SimpleDateFormat format = new SimpleDateFormat("yy/MM/dd HH:mm:ss");

    Date d1 = null;
    Date d2 = null;
    try {
        d1 = format.parse(dateStart);
        d2 = format.parse(dateStop);
    } catch (ParseException e) {
        e.printStackTrace();
    }

    // Get msec from each, and subtract.
    long diff = d2.getTime() - d1.getTime();
    long diffSeconds = diff / 1000 % 60;
    long diffMinutes = diff / (60 * 1000) % 60;
    long diffHours = diff / (60 * 60 * 1000);
    System.out.println("Time in seconds: " + diffSeconds + " seconds.");
    System.out.println("Time in minutes: " + diffMinutes + " minutes.");
    System.out.println("Time in hours: " + diffHours + " hours.");

spróbuj wykonać następujące czynności

{
        Date dt2 = new DateAndTime().getCurrentDateTime();

        long diff = dt2.getTime() - dt1.getTime();
        long diffSeconds = diff / 1000 % 60;
        long diffMinutes = diff / (60 * 1000) % 60;
        long diffHours = diff / (60 * 60 * 1000);
        int diffInDays = (int) ((dt2.getTime() - dt1.getTime()) / (1000 * 60 * 60 * 24));

        if (diffInDays > 1) {
            System.err.println("Difference in number of days (2) : " + diffInDays);
            return false;
        } else if (diffHours > 24) {

            System.err.println(">24");
            return false;
        } else if ((diffHours == 24) && (diffMinutes >= 1)) {
            System.err.println("minutes");
            return false;
        }
        return true;
}

Konwersję różnicy dat można lepiej obsłużyć za pomocą wbudowanej klasy Java, TimeUnit . Zapewnia narzędzia do tego:

Date startDate = // Set start date
Date endDate   = // Set end date

long duration  = endDate.getTime() - startDate.getTime();

long diffInSeconds = TimeUnit.MILLISECONDS.toSeconds(duration);
long diffInMinutes = TimeUnit.MILLISECONDS.toMinutes(duration);
long diffInHours = TimeUnit.MILLISECONDS.toHours(duration);
long diffInDays = TimeUnit.MILLISECONDS.toDays(duration);

Użyj biblioteki Joda-Time

DateTime startTime, endTime;
Period p = new Period(startTime, endTime);
long hours = p.getHours();
long minutes = p.getMinutes();

Joda Time ma pojęcie przedziału czasowego:

Interval interval = new Interval(oldTime, new Instant());

Jeszcze jeden przykład różnicy dat

Jeszcze jeden link

lub z Javą-8 (która zintegrowała koncepcje Joda-Time)

Instant start, end;//
Duration dur = Duration.between(start, stop);
long hours = dur.toHours();
long minutes = dur.toMinutes();

Oto, jak problem można rozwiązać w Javie 8, podobnie jak odpowiedź autorstwa shamimza.

Źródło: http://docs.oracle.com/javase/tutorial/datetime/iso/period.html

LocalDate today = LocalDate.now();
LocalDate birthday = LocalDate.of(1960, Month.JANUARY, 1);

Period p = Period.between(birthday, today);
long p2 = ChronoUnit.DAYS.between(birthday, today);

System.out.println("You are " + p.getYears() + " years, " + p.getMonths() + " months, and " + p.getDays() + " days old. (" + p2 + " days total)");

Kod generuje dane wyjściowe podobne do następujących:

You are 53 years, 4 months, and 29 days old. (19508 days total)

Musimy użyć LocalDateTime http://docs.oracle.com/javase/8/docs/api/java/time/LocalDateTime.html, aby uzyskać różnice godzinowe, minutowe i sekundowe.

Date d2 = new Date();
Date d1 = new Date(1384831803875l);

long diff = d2.getTime() - d1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000);
int diffInDays = (int) diff / (1000 * 60 * 60 * 24);

System.out.println(diffInDays+"  days");
System.out.println(diffHours+"  Hour");
System.out.println(diffMinutes+"  min");
System.out.println(diffSeconds+"  sec");

Możesz utworzyć metodę taką jak

public long getDaysBetweenDates(Date d1, Date d2){
return TimeUnit.MILLISECONDS.toDays(d1.getTime() - d2.getTime());
}

Ta metoda zwróci liczbę dni między dwoma dniami.

Jak pisze Michael Borgwardt w swojej odpowiedzi tutaj :

int diffInDays = (int)( (newerDate.getTime() - olderDate.getTime()) 
                 / (1000 * 60 * 60 * 24) )

Pamiętaj, że działa to z datami UTC, więc różnica może być dniem wolnym, jeśli spojrzysz na daty lokalne. A sprawienie, aby działał poprawnie z lokalnymi datami, wymaga zupełnie innego podejścia ze względu na czas letni.

W Javie 8, można zrobić z DateTimeFormatter, Duration, i LocalDateTime. Oto przykład:

final String dateStart = "11/03/14 09:29:58";
final String dateStop = "11/03/14 09:33:43";

final DateTimeFormatter formatter = new DateTimeFormatterBuilder()
        .appendValue(ChronoField.MONTH_OF_YEAR, 2)
        .appendLiteral('/')
        .appendValue(ChronoField.DAY_OF_MONTH, 2)
        .appendLiteral('/')
        .appendValueReduced(ChronoField.YEAR, 2, 2, 2000)
        .appendLiteral(' ')
        .appendValue(ChronoField.HOUR_OF_DAY, 2)
        .appendLiteral(':')
        .appendValue(ChronoField.MINUTE_OF_HOUR, 2)
        .appendLiteral(':')
        .appendValue(ChronoField.SECOND_OF_MINUTE, 2)
        .toFormatter();

final LocalDateTime start = LocalDateTime.parse(dateStart, formatter);
final LocalDateTime stop = LocalDateTime.parse(dateStop, formatter);

final Duration between = Duration.between(start, stop);

System.out.println(start);
System.out.println(stop);
System.out.println(formatter.format(start));
System.out.println(formatter.format(stop));
System.out.println(between);
System.out.println(between.get(ChronoUnit.SECONDS));

Pomogło mi, mogę spróbować z tym, mam nadzieję, że będzie to pomocne. Daj mi znać, jeśli masz jakiekolwiek obawy.

Date startDate = java.util.Calendar.getInstance().getTime(); //set your start time
Date endDate = java.util.Calendar.getInstance().getTime(); // set  your end time

long duration = endDate.getTime() - startDate.getTime();


long diffInSeconds = TimeUnit.MILLISECONDS.toSeconds(duration);
long diffInMinutes = TimeUnit.MILLISECONDS.toMinutes(duration);
long diffInHours = TimeUnit.MILLISECONDS.toHours(duration);
long diffInDays = TimeUnit.MILLISECONDS.toDays(duration);

Toast.makeText(MainActivity.this, "Diff"
        + duration + diffInDays + diffInHours + diffInMinutes + diffInSeconds, Toast.LENGTH_SHORT).show(); **// Toast message for android .**

System.out.println("Diff" + duration + diffInDays + diffInHours + diffInMinutes + diffInSeconds); **// Print console message for Java .**

To jest kod:

        String date1 = "07/15/2013";
        String time1 = "11:00:01";
        String date2 = "07/16/2013";
        String time2 = "22:15:10";
        String format = "MM/dd/yyyy HH:mm:ss";
        SimpleDateFormat sdf = new SimpleDateFormat(format);
        Date fromDate = sdf.parse(date1 + " " + time1);
        Date toDate = sdf.parse(date2 + " " + time2);

        long diff = toDate.getTime() - fromDate.getTime();
        String dateFormat="duration: ";
        int diffDays = (int) (diff / (24 * 60 * 60 * 1000));
        if(diffDays>0){
            dateFormat+=diffDays+" day ";
        }
        diff -= diffDays * (24 * 60 * 60 * 1000);

        int diffhours = (int) (diff / (60 * 60 * 1000));
        if(diffhours>0){
            dateFormat+=diffhours+" hour ";
        }
        diff -= diffhours * (60 * 60 * 1000);

        int diffmin = (int) (diff / (60 * 1000));
        if(diffmin>0){
            dateFormat+=diffmin+" min ";
        }
        diff -= diffmin * (60 * 1000);

        int diffsec = (int) (diff / (1000));
        if(diffsec>0){
            dateFormat+=diffsec+" sec";
        }
        System.out.println(dateFormat);

a wyjście to:

duration: 1 day 11 hour 15 min 9 sec

w odniesieniu do aktualizacji odpowiedzi shamima jest to metoda, która wykonuje to zadanie bez korzystania z biblioteki innej firmy. Po prostu skopiuj metodę i użyj

public static String getDurationTimeStamp(String date) {

        String timeDifference = "";

        //date formatter as per the coder need
        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

        //parse the string date-ti
        // me to Date object
        Date startDate = null;
        try {
            startDate = sdf.parse(date);
        } catch (ParseException e) {
            e.printStackTrace();
        }

        //end date will be the current system time to calculate the lapse time difference
        //if needed, coder can add end date to whatever date
        Date endDate = new Date();

        System.out.println(startDate);
        System.out.println(endDate);

        //get the time difference in milliseconds
        long duration = endDate.getTime() - startDate.getTime();

        //now we calculate the differences in different time units
        //this long value will be the total time difference in each unit
        //i.e; total difference in seconds, total difference in minutes etc...
        long diffInSeconds = TimeUnit.MILLISECONDS.toSeconds(duration);
        long diffInMinutes = TimeUnit.MILLISECONDS.toMinutes(duration);
        long diffInHours = TimeUnit.MILLISECONDS.toHours(duration);
        long diffInDays = TimeUnit.MILLISECONDS.toDays(duration);

        //now we create the time stamps depending on the value of each unit that we get
        //as we do not have the unit in years,
        //we will see if the days difference is more that 365 days, as 365 days = 1 year
        if (diffInDays > 365) {
            //we get the year in integer not in float
            //ex- 791/365 = 2.167 in float but it will be 2 years in int
            int year = (int) (diffInDays / 365);
            timeDifference = year + " years ago";
            System.out.println(year + " years ago");
        }
        //if days are not enough to create year then get the days
        else if (diffInDays > 1) {
            timeDifference = diffInDays + " days ago";
            System.out.println(diffInDays + " days ago");
        }
        //if days value<1 then get the hours
        else if (diffInHours > 1) {
            timeDifference = diffInHours + " hours ago";
            System.out.println(diffInHours + " hours ago");
        }
        //if hours value<1 then get the minutes
        else if (diffInMinutes > 1) {
            timeDifference = diffInMinutes + " minutes ago";
            System.out.println(diffInMinutes + " minutes ago");
        }
        //if minutes value<1 then get the seconds
        else if (diffInSeconds > 1) {
            timeDifference = diffInSeconds + " seconds ago";
            System.out.println(diffInSeconds + " seconds ago");
        }

        return timeDifference;
// that's all. Happy Coding :)
    }

Niedawno rozwiązałem podobny problem prostą metodą.

public static void main(String[] args) throws IOException, ParseException {
        TimeZone utc = TimeZone.getTimeZone("UTC");
        Calendar calendar = Calendar.getInstance(utc);
        Date until = calendar.getTime();
        calendar.add(Calendar.DAY_OF_MONTH, -7);
        Date since = calendar.getTime();
        long durationInSeconds  = TimeUnit.MILLISECONDS.toSeconds(until.getTime() - since.getTime());

        long SECONDS_IN_A_MINUTE = 60;
        long MINUTES_IN_AN_HOUR = 60;
        long HOURS_IN_A_DAY = 24;
        long DAYS_IN_A_MONTH = 30;
        long MONTHS_IN_A_YEAR = 12;

        long sec = (durationInSeconds >= SECONDS_IN_A_MINUTE) ? durationInSeconds % SECONDS_IN_A_MINUTE : durationInSeconds;
        long min = (durationInSeconds /= SECONDS_IN_A_MINUTE) >= MINUTES_IN_AN_HOUR ? durationInSeconds%MINUTES_IN_AN_HOUR : durationInSeconds;
        long hrs = (durationInSeconds /= MINUTES_IN_AN_HOUR) >= HOURS_IN_A_DAY ? durationInSeconds % HOURS_IN_A_DAY : durationInSeconds;
        long days = (durationInSeconds /= HOURS_IN_A_DAY) >= DAYS_IN_A_MONTH ? durationInSeconds % DAYS_IN_A_MONTH : durationInSeconds;
        long months = (durationInSeconds /=DAYS_IN_A_MONTH) >= MONTHS_IN_A_YEAR ? durationInSeconds % MONTHS_IN_A_YEAR : durationInSeconds;
        long years = (durationInSeconds /= MONTHS_IN_A_YEAR);

        String duration = getDuration(sec,min,hrs,days,months,years);
        System.out.println(duration);
    }
    private static String getDuration(long secs, long mins, long hrs, long days, long months, long years) {
        StringBuffer sb = new StringBuffer();
        String EMPTY_STRING = "";
        sb.append(years > 0 ? years + (years > 1 ? " years " : " year "): EMPTY_STRING);
        sb.append(months > 0 ? months + (months > 1 ? " months " : " month "): EMPTY_STRING);
        sb.append(days > 0 ? days + (days > 1 ? " days " : " day "): EMPTY_STRING);
        sb.append(hrs > 0 ? hrs + (hrs > 1 ? " hours " : " hour "): EMPTY_STRING);
        sb.append(mins > 0 ? mins + (mins > 1 ? " mins " : " min "): EMPTY_STRING);
        sb.append(secs > 0 ? secs + (secs > 1 ? " secs " : " secs "): EMPTY_STRING);
        sb.append("ago");
        return sb.toString();
    }

I zgodnie z oczekiwaniami to drukuje: 7 days ago.

To jest program, który napisałem, który pobiera liczbę dni między 2 datami (bez czasu).

import java.util.Scanner;
public class HelloWorld {
 public static void main(String args[]) {
  Scanner s = new Scanner(System.in);
  System.out.print("Enter starting date separated by dots: ");
  String inp1 = s.nextLine();
  System.out.print("Enter ending date separated by dots: ");
  String inp2 = s.nextLine();
  int[] nodim = {
   0,
   31,
   28,
   31,
   30,
   31,
   30,
   31,
   31,
   30,
   31,
   30,
   31
  };
  String[] inpArr1 = split(inp1);
  String[] inpArr2 = split(inp2);
  int d1 = Integer.parseInt(inpArr1[0]);
  int m1 = Integer.parseInt(inpArr1[1]);
  int y1 = Integer.parseInt(inpArr1[2]);
  int d2 = Integer.parseInt(inpArr2[0]);
  int m2 = Integer.parseInt(inpArr2[1]);
  int y2 = Integer.parseInt(inpArr2[2]);
  if (y1 % 4 == 0) nodim[2] = 29;
  int diff = m1 == m2 && y1 == y2 ? d2 - (d1 - 1) : (nodim[m1] - (d1 - 1));
  int mm1 = m1 + 1, mm2 = m2 - 1, yy1 = y1, yy2 = y2;
  for (; yy1 <= yy2; yy1++, mm1 = 1) {
   mm2 = yy1 == yy2 ? (m2 - 1) : 12;
   if (yy1 % 4 == 0) nodim[2] = 29;
   else nodim[2] = 28;
   if (mm2 == 0) {
    mm2 = 12;
    yy2 = yy2 - 1;
   }
   for (; mm1 <= mm2 && yy1 <= yy2; mm1++) diff = diff + nodim[mm1];
  }
  System.out.print("No. of days from " + inp1 + " to " + inp2 + " is " + diff);
 }
 public static String[] split(String s) {
  String[] retval = {
   "",
   "",
   ""
  };
  s = s + ".";
  s = s + " ";
  for (int i = 0; i <= 2; i++) {
   retval[i] = s.substring(0, s.indexOf("."));
   s = s.substring((s.indexOf(".") + 1), s.length());
  }
  return retval;
 }
}

http://pastebin.com/HRsjTtUf

java.time.Duration

Nadal nie czułem, że żadna z odpowiedzi była dość aktualna i na temat. Oto współczesna odpowiedź wykorzystująca Durationz java.time, nowoczesnego API daty i czasu Javy (odpowiedzi MayurB i mkobit wspominają o tej samej klasie, ale żadna z nich nie konwertuje poprawnie na dni, godziny, minuty i minuty zgodnie z pytaniem).

    DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yy/MM/dd HH:mm:ss");
    
    String dateStart = "11/03/14 09:29:58";
    String dateStop = "11/03/14 09:33:43";

    ZoneId zone = ZoneId.systemDefault();
    ZonedDateTime startDateTime = LocalDateTime.parse(dateStart, formatter).atZone(zone);
    ZonedDateTime endDateTime = LocalDateTime.parse(dateStop, formatter).atZone(zone);
    
    Duration diff = Duration.between(startDateTime, endDateTime);
    if (diff.isZero()) {
        System.out.println("0 minutes");
    } else {
        long days = diff.toDays();
        if (days != 0) {
            System.out.print("" + days + " days ");
            diff = diff.minusDays(days);
        }
        long hours = diff.toHours();
        if (hours != 0) {
            System.out.print("" + hours + " hours ");
            diff = diff.minusHours(hours);
        }
        long minutes = diff.toMinutes();
        if (minutes != 0) {
            System.out.print("" + minutes + " minutes ");
            diff = diff.minusMinutes(minutes);
        }
        long seconds = diff.getSeconds();
        if (seconds != 0) {
            System.out.print("" + seconds + " seconds ");
        }
        System.out.println();
    }

Dane wyjściowe z tego przykładowego fragmentu kodu to:

3 minuty 45 sekund

Pamiętaj, że Durationdzień liczy się zawsze jako 24 godziny. Jeśli chcesz inaczej traktować anomalie czasowe, takie jak przejścia w czasie letnim, rozwiązania obejmują (1) użyj ChronoUnit.DAYS(2) Użyj Period(3) Use LocalDateTime instead ofZonedDateTime` (może to być traktowane jako hack).

Powyższy kod działa z Javą 8 i ThreeTen Backport, tym backportem java.time do Javy 6 i 7. Z Java 9 może być możliwe napisanie go trochę ładniej przy użyciu metod toHoursPart, toMinutesPartitoSecondsPart dodaje tam.

Wyjaśnię dalej w jeden z dni, kiedy będę miał czas, może nie wcześniej niż w przyszłym tygodniu.

   // calculating the difference b/w startDate and endDate
        String startDate = "01-01-2016";
        String endDate = simpleDateFormat.format(currentDate);

        date1 = simpleDateFormat.parse(startDate);
        date2 = simpleDateFormat.parse(endDate);

        long getDiff = date2.getTime() - date1.getTime();

        // using TimeUnit class from java.util.concurrent package
        long getDaysDiff = TimeUnit.MILLISECONDS.toDays(getDiff);

Jak obliczyć różnicę między dwiema datami w Javie