Czy istnieje sposób, aby sprawdzić, czy ciąg znaków w JS jest jednym pojedynczym emoji?


20

Pytanie jest proste: mam ciąg znaków str, jak sprawdzić, czy strjest to jedno emoji i nic więcej? Dodatkowo wolałbym nie używać innej biblioteki.

Mecz "🍎", "⛹🏿‍♂️", "3️⃣"ale nie "🍓a", "𝕒","🍌🍀"

Mam problem ze znalezieniem rozwiązania, ale próbowałem do tej pory kilku rzeczy:


Próba rozwiązania 1 - Baw się wokół długości i ...operatora

Dowiedziałem się, że emoji zajmują więcej niż jeden bajt, niektóre nawet 4 bajty lub więcej ... i możemy to zmierzyć za pomocą właściwości ciągu length:

console.log("🍎".length); // 2
console.log("🛡️".length); // 3
console.log("⛹🏿‍♂️".length); // 6

Potem dowiedziałem się, że ...operator bierze to pod uwagę i poprawnie oddziela emoji w tablicy - mogłem wtedy zobaczyć właściwość tablicy wynikowej lengthi sprawdzić, czy są one różne.

str = "⛹🏿‍♂️";
if (str.length !== [...str].length) {
  // is emoji?
} else {
  // is not emoji
}

Ale to nie sprawdza innych wielobajtowych znaków, takich jak 𝕡których długość wynosi 2. Ponadto niektóre emoji nadal dziwnie się rozdzielały.


Próba rozwiązania 2 - Regex, wyrażenia regularne

Oczywiście regex byłby rzeczą godną uwagi, ale wciąż nie znalazłem realnego rozwiązania.

Wyrażenie regularne tej odpowiedzi\u00a9|\u00ae|[\u2000-\u3300]|\ud83c[\ud000-\udfff]|\ud83d[\ud000-\udfff]|\ud83e[\ud000-\udfff] działa idealnie w celu wykrycia, czy łańcuch ma emoji, ale zastosowany w mojej sytuacji powoduje wiele problemów. Oto moje testy:

Część A - Bez początku / końca wyrażenia regularnego ( ^i $)

  • 2A.1 str.match(regex) jest bardzo niespójny, rozkłada niektóre emoji i inne bezużyteczne. Nie widzę sposobu, aby dowiedzieć się, czy zawiera nawet znaki inne niż emoji lub czy zawiera więcej niż jeden emoji:
let regex = /(\u00a9|\u00ae|[\u2000-\u3300]|\ud83c[\ud000-\udfff]|\ud83d[\ud000-\udfff]|\ud83e[\ud000-\udfff])/;

console.log("5️⃣".match(regex)); // [ '⃣', '⃣', index: 2, input: '5️⃣' ]
console.log("💡".match(regex)); // [ '💡', '💡', index: 0, input: '💡' ]
console.log("🌡️🌡️".match(regex)); // [ '🌡', '🌡', index: 0, input: '🌡️🌡️' ]
console.log("a⛅".match(regex)); // [ '⛅', '⛅', index: 1, input: 'a⛅' ]
  • 2A.2 regex.test(str) zwraca wartość true za każdym razem, gdy w ciągu znajduje się emoji, czego nie szukam:
let regex = /(\u00a9|\u00ae|[\u2000-\u3300]|\ud83c[\ud000-\udfff]|\ud83d[\ud000-\udfff]|\ud83e[\ud000-\udfff])/;

console.log(regex.test("5️⃣")); // true - correct
console.log(regex.test("a")); // false - correct
console.log(regex.test("🌡️🌡️")); // true - should be false
console.log(regex.test("hello ⛅!")); // true - should be false

Część B - Z początkiem / końcem wyrażenia regularnego ciągu ( ^i $)

  • 2B.1 z jakiegoś powodu str.match(regex)powraca nullna niektórych emoji. Nie mam pojęcia, dlaczego, ale str.match(regex)zakładam, że ma to jakiś związek z tym, dlaczego miałby rozbić te emoji w części A:
let regex = /^(\u00a9|\u00ae|[\u2000-\u3300]|\ud83c[\ud000-\udfff]|\ud83d[\ud000-\udfff]|\ud83e[\ud000-\udfff])$/;

console.log("5️⃣".match(regex)); // null
console.log("💡".match(regex)); // [ '💡', '💡', index: 0, input: '💡' ]
console.log("🌡️".match(regex)); // null
console.log("⛅".match(regex)); // [ '⛅', '⛅', index: 1, input: 'a⛅' ]
console.log("🍌🍀".match(regex)); // null
  • 2B.2 regex.test(str) powróci falsena tych samych emotikony gdzie go zwrócić nullna str.match(regex):
let regex = /^(\u00a9|\u00ae|[\u2000-\u3300]|\ud83c[\ud000-\udfff]|\ud83d[\ud000-\udfff]|\ud83e[\ud000-\udfff])$/;

console.log(regex.test("5️⃣")); // false - should be true
console.log(regex.test("💡")); // true - correct
console.log(regex.test("🌡️")); // false - should be true
console.log(regex.test("⛅")); // true - correct
console.log(regex.test("🍌🍀")); // false - correct

Część C - Inne wyrażenia regularne

  • Znalazłem ten, ale daje podobne niespójności, choć nie takie same /(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|[\ud83c[\ude01\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|[\ud83c[\ude32\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|[\ud83c[\ude50\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])/g:
let regex = /^(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|[\ud83c[\ude01\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|[\ud83c[\ude32\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|[\ud83c[\ude50\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])$/g

console.log(regex.test("5️⃣")); // true - correct
console.log(regex.test("💡")); // false - should be true
console.log(regex.test("🌡️")); // false - should be true
console.log(regex.test("⛅")); // true - correct
console.log(regex.test("🍌🍀")); // false - correct
  • To również psuje się okropnie (druga zmiana testu na podstawie pierwszego testu?)
let regex = /^(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|[\ud83c[\ude01\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|[\ud83c[\ude32\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|[\ud83c[\ude50\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])$/g

console.log(regex.test("⛹🏿‍♂️")); // false
console.log(regex.test("⛅")); // true
let regex = /^(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|[\ud83c[\ude01\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|[\ud83c[\ude32\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|[\ud83c[\ude50\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])$/g;

console.log(regex.test("⛹")); // true
console.log(regex.test("⛅")); // false

Czy istnieje sposób na obejście tego całego bałaganu emoji / unicode / regex? Czy biblioteki / api to jedyny sposób? Jak oni to robią?



2
Osobiście uważam, że utrzymywanie wyrażenia regularnego nie jest zbyt dobrym pomysłem, chyba że generujesz go na podstawie specyfikacji Unicode . Istnieją już biblioteki, które to robią. Zobacz emoji-regex i emoji.json .
Jake Holzinger

Dziękuję Wiktor Stribiżew, że wyrażenie regularne działa idealnie! Czy mogę wiedzieć, skąd to masz?
luxluxdev,

1
Jest czas i miejsce dla bibliotek. IMHO to jedna z nich. Koszt utrzymania zależności między wersjami i rozmiarem pliku wydaje się więcej niż przeważony, gdy ktoś inny rozwiązuje ten bardzo złożony problem.
Chris,

1
Re: „jak to robią” biblioteka, do której odwołuje się Daniel Vickers: unicode.org/reports/tr29/#Default_Grapheme_Cluster_Table
Chris,

Odpowiedzi:


1

Korzystając z tej biblioteki: https://github.com/foliojs/grapheme-breaker spróbuj:

var str = "⛹🏿‍♂️";
var Grapheme = require('grapheme-splitter');
var splitter = new Grapheme();
console.log(splitter.splitGraphemes(str).length);

a długość powinna zwrócić 1.


Ta biblioteka jest niesamowita, ale jest nieaktywna od roku, jednak jest inspirowana przez github.com/foliojs/grapheme-breaker, który był ostatnio bardzo aktywny :) ( usunąłem mój stary komentarz, ponieważ miał zły link)
luxluxdev

Dzięki za to zaktualizowałem również link w mojej odpowiedzi.
Daniel Vickers

1

Emoji są określone w UAX # 51. Właściwość \p{Emoji}powinna działać, ale nie działa.

Zrób to ciężko. Analiza emoji-*.txt:

perl -C -lne'
    if (my ($c) = $_ =~ /^((?:(?:[[:xdigit:]]+ )|[[:xdigit:]]+\.\.)[[:xdigit:]]+)/) {
        if ($c =~ /\.\./) { # ranges
             my ($f, $t) = map { hex } split /\.\./, $c;
             print for map { chr } $f..$t;
        } else { # sequences
             print join "", map { chr hex } split /\s+/, $c;
        }
    }
' emoji-*.txt

To daje nam oddzielną listę wszystkich emoji. Użycie Regexp :: Assemble :: Compressed daje wynik

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}\u{FE0F}]?|\u{1F554}[\u{FE0E}\u{FE0F}]?|\u{1F555}[\u{FE0E}\u{FE0F}]?|\u{1F556}[\u{FE0E}\u{FE0F}]?|\u{1F557}[\u{FE0E}\u{FE0F}]?|\u{1F558}[\u{FE0E}\u{FE0F}]?|\u{1F559}[\u{FE0E}\u{FE0F}]?|\u{1F55A}[\u{FE0E}\u{FE0F}]?|\u{1F55B}[\u{FE0E}\u{FE0F}]?|\u{1F55C}[\u{FE0E}\u{FE0F}]?|\u{1F55D}[\u{FE0E}\u{FE0F}]?|\u{1F55E}[\u{FE0E}\u{FE0F}]?|\u{1F55F}[\u{FE0E}\u{FE0F}]?|\u{1F560}[\u{FE0E}\u{FE0F}]?|\u{1F561}[\u{FE0E}\u{FE0F}]?|\u{1F562}[\u{FE0E}\u{FE0F}]?|\u{1F563}[\u{FE0E}\u{FE0F}]?|\u{1F564}[\u{FE0E}\u{FE0F}]?|\u{1F565}[\u{FE0E}\u{FE0F}]?|\u{1F566}[\u{FE0E}\u{FE0F}]?|\u{1F567}[\u{FE0E}\u{FE0F}]?|\u{1F56F}[\u{FE0E}\u{FE0F}]?|\u{1F570}[\u{FE0E}\u{FE0F}]?|\u{1F573}[\u{FE0E}\u{FE0F}]?|\u{1F576}[\u{FE0E}\u{FE0F}]?|\u{1F577}[\u{FE0E}\u{FE0F}]?|\u{1F578}[\u{FE0E}\u{FE0F}]?|\u{1F579}[\u{FE0E}\u{FE0F}]?|\u{1F58A}[\u{FE0E}\u{FE0F}]?|\u{1F58B}[\u{FE0E}\u{FE0F}]?|\u{1F58C}[\u{FE0E}\u{FE0F}]?|\u{1F58D}[\u{FE0E}\u{FE0F}]?|\u{1F5B1}[\u{FE0E}\u{FE0F}]?|\u{1F5B2}[\u{FE0E}\u{FE0F}]?|\u{1F5C2}[\u{FE0E}\u{FE0F}]?|\u{1F5C3}[\u{FE0E}\u{FE0F}]?|\u{1F5C4}[\u{FE0E}\u{FE0F}]?|\u{1F5D1}[\u{FE0E}\u{FE0F}]?|\u{1F5D2}[\u{FE0E}\u{FE0F}]?|\u{1F5D3}[\u{FE0E}\u{FE0F}]?|\u{1F5DC}[\u{FE0E}\u{FE0F}]?|\u{1F5DD}[\u{FE0E}\u{FE0F}]?|\u{1F5DE}[\u{FE0E}\u{FE0F}]?|\u{1F5FA}[\u{FE0E}\u{FE0F}]?|\u{1F610}[\u{FE0E}\u{FE0F}]?|\u{1F687}[\u{FE0E}\u{FE0F}]?|\u{1F68D}[\u{FE0E}\u{FE0F}]?|\u{1F691}[\u{FE0E}\u{FE0F}]?|\u{1F694}[\u{FE0E}\u{FE0F}]?|\u{1F698}[\u{FE0E}\u{FE0F}]?|\u{1F6AD}[\u{FE0E}\u{FE0F}]?|\u{1F6B2}[\u{FE0E}\u{FE0F}]?|\u{1F6B9}[\u{FE0E}\u{FE0F}]?|\u{1F6BA}[\u{FE0E}\u{FE0F}]?|\u{1F6BC}[\u{FE0E}\u{FE0F}]?|\u{1F6CB}[\u{FE0E}\u{FE0F}]?|\u{1F6CD}[\u{FE0E}\u{FE0F}]?|\u{1F6CE}[\u{FE0E}\u{FE0F}]?|\u{1F6CF}[\u{FE0E}\u{FE0F}]?|\u{1F6E0}[\u{FE0E}\u{FE0F}]?|\u{1F6E1}[\u{FE0E}\u{FE0F}]?|\u{1F6E2}[\u{FE0E}\u{FE0F}]?|\u{1F6E3}[\u{FE0E}\u{FE0F}]?|\u{1F6E4}[\u{FE0E}\u{FE0F}]?|\u{1F6E5}[\u{FE0E}\u{FE0F}]?|\uA9[\u{FE0E}\u{FE0F}]|\uAE[\u{FE0E}\u{FE0F}]|\u{203C}[\u{FE0E}\u{FE0F}]|\u{2049}[\u{FE0E}\u{FE0F}]|\u{2122}[\u{FE0E}\u{FE0F}]|\u{2139}[\u{FE0E}\u{FE0F}]|\u{2328}[\u{FE0E}\u{FE0F}]|\u{23CF}[\u{FE0E}\u{FE0F}]|\u{24C2}[\u{FE0E}\u{FE0F}]|\u{25B6}[\u{FE0E}\u{FE0F}]|\u{25C0}[\u{FE0E}\u{FE0F}]|\u{260E}[\u{FE0E}\u{FE0F}]|\u{2611}[\u{FE0E}\u{FE0F}]|\u{2618}[\u{FE0E}\u{FE0F}]|\u{2620}[\u{FE0E}\u{FE0F}]|\u{2626}[\u{FE0E}\u{FE0F}]|\u{262A}[\u{FE0E}\u{FE0F}]|\u{2640}[\u{FE0E}\u{FE0F}]|\u{2642}[\u{FE0E}\u{FE0F}]|\u{265F}[\u{FE0E}\u{FE0F}]|\u{2660}[\u{FE0E}\u{FE0F}]|\u{2663}[\u{FE0E}\u{FE0F}]|\u{2668}[\u{FE0E}\u{FE0F}]|\u{267B}[\u{FE0E}\u{FE0F}]|\u{267E}[\u{FE0E}\u{FE0F}]|\u{267F}[\u{FE0E}\u{FE0F}]|\u{2695}[\u{FE0E}\u{FE0F}]|\u{2699}[\u{FE0E}\u{FE0F}]|\u{26C8}[\u{FE0E}\u{FE0F}]|\u{26D1}[\u{FE0E}\u{FE0F}]|\u{26FD}[\u{FE0E}\u{FE0F}]|\u{2702}[\u{FE0E}\u{FE0F}]|\u{270F}[\u{FE0E}\u{FE0F}]|\u{2712}[\u{FE0E}\u{FE0F}]|\u{2714}[\u{FE0E}\u{FE0F}]|\u{2716}[\u{FE0E}\u{FE0F}]|\u{271D}[\u{FE0E}\u{FE0F}]|\u{2721}[\u{FE0E}\u{FE0F}]|\u{2744}[\u{FE0E}\u{FE0F}]|\u{2747}[\u{FE0E}\u{FE0F}]|\u{2757}[\u{FE0E}\u{FE0F}]|\u{27A1}[\u{FE0E}\u{FE0F}]|\u{2B50}[\u{FE0E}\u{FE0F}]|\u{2B55}[\u{FE0E}\u{FE0F}]|\u{3030}[\u{FE0E}\u{FE0F}]|\u{303D}[\u{FE0E}\u{FE0F}]|\u{3297}[\u{FE0E}\u{FE0F}]|\u{3299}[\u{FE0E}\u{FE0F}]|\u{1F004}[\u{FE0E}\u{FE0F}]|\u{1F21A}[\u{FE0E}\u{FE0F}]|\u{1F22F}[\u{FE0E}\u{FE0F}]|\u{1F587}[\u{FE0E}\u{FE0F}]|\u{1F5A5}[\u{FE0E}\u{FE0F}]|\u{1F5A8}[\u{FE0E}\u{FE0F}]|\u{1F5BC}[\u{FE0E}\u{FE0F}]|\u{1F5E1}[\u{FE0E}\u{FE0F}]|\u{1F5E3}[\u{FE0E}\u{FE0F}]|\u{1F5E8}[\u{FE0E}\u{FE0F}]|\u{1F5EF}[\u{FE0E}\u{FE0F}]|\u{1F5F3}[\u{FE0E}\u{FE0F}]|\u{1F6E9}[\u{FE0E}\u{FE0F}]|\u{1F6F0}[\u{FE0E}\u{FE0F}]|\u{1F6F3}[\u{FE0E}\u{FE0F}]|\u{1F1F4}\u{1F1F2}?|\u{1F1F6}\u{1F1E6}?|\u{1F1FD}\u{1F1F0}?|\u{1F46F}\u{200D}?|\u{1F93C}\u{200D}?|\u{1F9DE}\u{200D}?|\u{1F9DF}\u{200D}?)$/u

Dzięki za wyjaśnienie, naprawdę pomocne! Wydaje mi się jednak, że nie mogę sprawić, by wynikowy regex działał, ponieważ występuje błąd wszędzie tam, gdzie go wypróbuję.
luxluxdev,
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