To proste zadanie. Biorąc pod uwagę dodatnią lub ujemną liczbę rzeczywistą, zaokrąglij ją do następnej liczby całkowitej bliższej zera.

Wyzwanie

• Przyjmij dane wejściowe za pomocą dowolnej rozsądnej formy (standardowa, funkcja itp.) Jednej dodatniej lub ujemnej liczby rzeczywistej.

• Zaokrąglaj tę liczbę „w kierunku zera” - oznacza to, że jeśli jest dodatnia, zaokrąglisz w dół, a jeśli jest ujemna, zaokrąglisz w górę.

• Zwróć numer lub wyślij go do konsoli.

Przypadki testowe

 1.1   =>  1
-1.1   => -1
 500.4 =>  500
-283.5 => -283
 50    =>  50
-50    => -50

Zasady

• To jest golf golfowy , więc najmniejszy wynik w bajtach wygrywa.

• Pamiętaj o standardowych lukach .

Baw się dobrze! _{^{kolejne wyzwania Jimmy już wkrótce}}

Galaretka , 1 bajt

r

Pełny program (jako monadyczny link zwraca listę o długości jeden).

Wypróbuj online!

W jaki sposób?

r - Main Link: number, X           e.g. -7.999
r - inclusive range between left (X) and right (X) (implicit cast to integer of inputs)
  -  = [int(X):int(X)] = [int(X)]       [-7]
  - implicit (smashing) print            -7

Python 3 , 3 bajty

int

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Obcina cyfry po przecinku.

UWAGA: To banalna odpowiedź. Proszę spojrzeć na inne odpowiedzi przed głosowaniem

Python 2 , 3 bajty

int

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Perl 5 -p056l15 , 2 bajty

<>

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Jak to działa?

-056   # (CLI) Make "." the input record separator
-l15   # (CLI) Make "\n" the output record separator
       # (otherwise it would use the input separator)
-p     # (CLI) Implicitly read $_ from STDIN
<>     # Read the second input field and do nothing with it
-p     # (CLI) Output $_ to STDOUT

Lub jeśli wolisz bardziej tradycyjną odpowiedź:

Perl 5 , 6 bajtów

$_=int

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Labirynt i sześciokąt , 3 bajty

Dzięki FryAmTheEggman za zwrócenie uwagi, że napisałem trochę Sześciokąta!

?!@

Wypróbuj online!I wypróbuj online!

W jaki sposób?

Labirynt i Sześciokąty powiedzą ci tak wcześnie, jak to możliwe! ...

? - read and discard from STDIN until a digit, a - or a + is found. Then read as many characters as possible to form a valid (signed) decimal integer and push its value
! - pop a value and write its decimal representation to STDOUT
@ - exit the labyrinth

pieprzenie mózgu , 26 bajtów

,[.+++++[->+++++<]>+[,>]<]

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Wyprowadza znak końcowy, .jeśli liczba była dziesiętna

Nie ma zbyt wielu mądrych golfów, z wyjątkiem tego, że zamiast odejmować 46, aby sprawdzić, czy dana postać jest ., dodam 5 i mnożę przez 5, aby uzyskać 255, a następnie dodaj jeszcze jeden, aby przejść do zera. Odejmowanie 3, mnożenie przez 6 i odejmowanie 2 to ta sama liczba bajtów

C (tcc), 39 21 10 bajtów

Byłem właściwie zaskoczony, że nikt nie pomyślał o użyciu C.

f(float i){}

To nie jest funkcja tożsamości, jak się wydaje. Niejawny typ int funkcji f obcina zmiennoprzecinkowy.

TIO

Mniejsze prawdopodobieństwo oszukiwania ludzi, ale ma krótszy bajt:

f(int i){}

TIO

J , 6 bajtów

**<.@|

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Znak *razy *zaokrąglić w dół <.wartości bezwzględnej@|

Perl 6 , 4 bajty

*+|0

Funkcja anonimowa.

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Java (OpenJDK 8) , 15 bajtów 9 bajtów

s->(int)s

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dzięki @ kevin-cruijssen

Excel, 10 bajtów

=TRUNC(A1)

TRUNC obcina liczbę do liczby całkowitej, usuwając ułamkową część liczby.

R, 13 5 bytes

Thanks Robin Ryder

trunc

Try it online!

Retina 0.8.2, 5 bytes

\..*

Try it online! Link includes test cases.

Ruby, 11 bytes

proc &:to_i

I picked this one because it distinguishes itself from the lambdas that us Ruby golfers typically use (thankfully, it had the same bytecount as the "traditional" solution):

->n{n.to_i}

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ReRegex, 12 bytes

\..+//#input

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ReRegex is a programming language which matches and replaces over and over until there are no matches.

MATCH
    \.                                      The literal period/full stop char
    .+                                      Followed by one or more characters
REPLACE
    (nothing)                               Equivalent to removing the input
STRING TO REPEATEDLY MATCH/REPLACE UNTIL THERE ARE NO MATCHES
    #input                                  The input

JavaScript, 6 bytes

x=>x^0

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JavaScript, 8 bytes

Using built in is 2 bytes longer...

parseInt

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K (oK), 3 bytes

`i$

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Intel 8087 FPU machine code, 14 bytes

D9 2E 010C      FLDCW CW_RNDZ   ; modified CW register for round towards zero
D9 06 010E      FLD  A          ; load single precision value A into ST(0)
DF 16 0112      FIST B          ; store integer value of ST(0) into B

CW_RNDZ   DW    0F7FH           ; control word to round down

Input is single precision value in a memory location A (a DD), output is integer value at memory location B (a DW).

The 8087 must first be put into round towards zero mode by setting the control word (0F7FH). Then load the floating point value and store back to an integer.

Red, 4 bytes

to 1

Try it online!

Just converts the float to an integer (conversion by prototype)

Zsh, 10 bytes

<<<$[0^$1]

xor with 0. I came across this during another challenge recently. Try it online!

Does not work in Bash or POSIX sh (dash).

V (vim), 4 bytes

Á.#D

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Thanks @DJMcMayhem, 1 byte saved.

Keg, 19 17 13 bytes

This outputs some trailing unprintable characters. Also, this exits with an error. (Now we need reversed input!)

?'(:\.>')"([,

Whitespace (with vii5ard compiler), 18 17 bytes

[S S N
_Push_0][S N
S _Duplicate_0][T   N
T   T   _Read_STDIN_as_integer][T   T   T   _Retrieve_input][T  N
S T _Print_as_integer]

Letters S (space), T (tab), and N (new-line) added as highlighting only.
[..._some_action] added as explanation only.

Try it online. You'll have to copy-paste the code yourself (note that SE converts the tabs to a bunch of spaces!) in order to run the code at the online Whitespace-compiler vii5ard. When clicking run, it will ask for an input (i.e. -285.5), and after clicking enter it will continue and output -283.

Explanation in pseudo-code:

Integer i = STDIN as integer
Print i as integer

Whitespace can only use I/O as integers or single characters, so in this case it would read the input as integer and ignore any other trailing characters. I.e. -283.5 or -283abc5 would both be input (and thus output) as -283.

Unfortunately this above doesn't work on TIO for two reasons (all Whitespace compilers are slightly different..):

1. It will give a no parse error when we try to read an input as integer, which isn't an a valid integer. So, instead we'll read one character at a time, and stop (with an error) as soon as we've encountered the . or there is no more input (i.e. 50/-50).
2. In the vii5ard compiler it's also possible to push 0 with just SSN, whereas on TIO it requires an additional S or T: SSSN/SSTN. The first S is Enable Stack Manipulation; the second S is Push what follows as integer; the third S/T is positive/negative respectively; and any S/T after that (followed by an N) is the number we want to push in binary, where S=0 and T=1. For integer 0 this binary part doesn't matter, since it's 0 by default. But on TIO we'd still have to specify the positive/negative, and with most other Whitespace compilers like vii5ard not.

Whitespace (with TIO compiler), 48 bytes

[N
S S N
_Create_Label_LOOP][S S S N
_Push_0][S N
S _Duplicate_0][T   N
T   S _Read_STDIN_as_character][T   T   T   _Retrieve_input][S N
S _Duplicate_input][S S S T S T T   T   S N
_Push_46_.][T   S S T   _Subtract][N
T   S S N
_If_0_Jump_to_Label_EXIT][T N
S S _Print_as_character][N
S N
N
_Jump_to_Label_LOOP]

Letters S (space), T (tab), and N (new-line) added as highlighting only.
[..._some_action] added as explanation only.

Try it online (with raw spaces, tabs and new-lines only).

Explanation in pseudo-code:

Start LOOP:
  Character c = STDIN as character
  If(c == '.'):
    Exit program
  Print c as character
  Go to the next iteration of LOOP

Pip, 5 bytes

a//:1

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C# (Visual C# Interactive Compiler), 9 bytes

n=>(int)n

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Scala, 7 bytes

_.toInt

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05AB1E, 1 byte

ï

In the legacy version (which is written in Python), the cast to integer builtin works as expected to truncate the decimal values.

Try it online.

In the new version of 05AB1E (written in Elixir) it only works on strings (even though integers/decimals/strings should all be interchangeable, unless sorting lexicographical vs numeric for example). Guess I can report a bug to @Adnan..

Try it online to compare integer/decimal input (giving incorrect result) vs string inputs (giving correct results).

Aheui (esotope), 9 bytes

방망희

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Basic idea from that of triangular answer (or any other languages takes numeric input as integer).

Fun fact. 방망희(pronounced bang-mang-heui(a of ark)) sounds almost same as 방망이(pronounced bang-mang-i(a of ark, i sounds like E), which means bat.

How does it works?

방 takes number as integer.

망 prints value as number.

희 terminates program.

PowerShell, 19 bytes

$args-replace'\..*'

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PowerShell by default does bankers' rounding, which is pretty much the opposite of how many other languages do rounding. So, traditionally we'd use [Math]::Truncate() to strip the decimal point and any decimal part and achieve the "to zero" rounding we're interested in here. However, that's a bit long, so using this tip, we can round-toward-zero by implicitly casting the input to a string, performing a regex -replace to get rid of the period and anything after it, and leaving the output on the pipeline for implicit printing.

Triangular, 3 bytes

$.%

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Triangular takes numeric input as an integer; any decimal values are truncated. If it's acceptable to just leave the input on the stack without printing it, then this solution can instead be:

Triangular, 1 byte

$

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